-8m^2+18=0

Solution for -8m^2+18=0 equation:

-8m^2+18=0

a = -8; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-8)·18
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-8}=\frac{-24}{-16}
=1+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-8}=\frac{24}{-16}
=-1+1/2
$